Introduction
You might
have learned about testing the population mean/s. In this article, you will
learn how to perform the hypothesis test for population standard deviation.
Consider the following scenarios.
Studying
the volatility in the rates of returns for a stock A, testing whether the
standard deviation of the volume of the water tanks is different from 1 cm3,
testing the variance of weights of people in a gym, etc. In all these
situations, either the population variance or the standard deviation are parameter/s
of interest.
To test the
claim about population variance or population standard deviation, we collect
the sampled data from population/s. Then we make the inferences and conclusions
based on these samples. There are some assumptions that should be satisfied to
carry out variance testing.
Assumptions for chi-square test for variation
- The data should be a simple random sample.
- The observations in the data should be independent.
- The population should follow the normal distribution.
In
addition, if the sample size is n < 0.05*N then this assures the observations
are independent.
If the data
follows all these conditions, then one can use the chi-square variance test. Using
the chi-square distribution, you can test the claim about population variance
or population standard deviation for a single population. The chi-square test
is not applicable for comparing two population variances/standard deviations.
Steps
Let us see
what the steps are involved in the chi-square test for variation one by one.
Step 1: Fix the null and alternative hypotheses
The null
and alternative hypotheses for proportion testing are as follows.
Step
2: Chose the correct formula to calculate the test statistic
Use the
following formula to find the test statistic for the chi-square test for variation.
The same formula is used while testing population variance and population
standard deviation.
Here s² is
the sample variance, σ02 is the standard deviation and n is the sample
size. The test statistic in chi-square tests follows the chi-square
distribution with (n-1) degrees of freedom.
Step 3: Fix the significance level (α)
Most of the
time the value of α is given in the question. If you do not know the value of
α then just take α=0.05.
Step
4: Find the critical value/s or p-value
The
critical values or p-value are essential in making the decision, whether to
reject or fail to reject the null hypothesis. You can use either the statistical
tables or technology like excel or TI84 calculator or R-Studio, etc. to find
critical values as well as p-value.
Step 5: Make the decisions based on critical value/ p-value
Based
on critical values:
Using
critical values, you can decide the rejection region. If the value of test
statistic found in step 2 lies in the rejection region, then reject the null
hypothesis at α level of significance, otherwise fail to reject the null
hypothesis.
Based
on p-value:
If the
p-value ≤ α then reject the null hypothesis otherwise fail to reject the null
hypothesis.
Step
6: Conclusion based on the decision
If you reject
the null hypothesis then write that, “There is sufficient evidence to
support the claim in alternative hypothesis”. This is exactly the same as
writing, “There is sufficient evidence to reject the claim in null
hypothesis”.
If you fail
to reject the null hypothesis then write that, “There is insufficient
evidence to support the claim in alternative hypothesis”. This is exactly the same as writing, “There is insufficient evidence to reject the claim in null
hypothesis”.
Write the
conclusion based on the test that you are using.
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